Question 1040317: complete the square 25x^2-9y^2+50x+250=0 and show work. do I use 0 for the y? Found 2 solutions by Aldorozos, ikleyn:Answer by Aldorozos(172) (Show Source): You can put this solution on YOUR website! The quadratic equation has a format of ax^2+bx+c = 0
For the equation of 25x^2-9y^2+50x+250=0 to look like ax^2+bx+c = 0 is to consider -9y^2 as a constant just like 250 which is a constant. If we add these two constants we get 250-9y^2 for the simplicity we can look at 250-9y^2 as another constant like C. Then in this case we can rewrite the equation
25x^2-9y^2+50x+250 = 25x^2+50x +c
Now we use quadratic equation to solve this. x= [-50+and - sqrt(-50)^2 -4(25)(c)]/2(25)
x = [-50+&-sqrt2500-4(25)(250-9y^2)]/50 We can multiply this a little more. However, we won't be able to have any number for x unless we know what y is. Answer by ikleyn(52781) (Show Source): You can put this solution on YOUR website! .
complete the square 25x^2-9y^2+50x+250=0 and show work. do I use 0 for the y?
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= .
Complete the square in the left side:
=
= - =
= - =
= - + 225.