SOLUTION: The graph of y=ax^2 + bx + c is a parabola with vertical axis of symmetry. The vertex of this parabola is (2,3) and the parabola contains the point (4,4). Find the value of y when
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Question 1038746: The graph of y=ax^2 + bx + c is a parabola with vertical axis of symmetry. The vertex of this parabola is (2,3) and the parabola contains the point (4,4). Find the value of y when x=6.
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Use the vertex form.
^2\ +\ k)
where )
is the vertex of the parabola.
^2\ +\ 3)
Substitute the coordinates for (4,4):
^2\ +\ 3)
and solve for 
Then you can insert the value of and then expand and rearrange to get the standard form of the function if you wish.
John
My calculator said it, I believe it, that settles it
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