SOLUTION: My question is given the equation s=-16t^2+initial velocity x t+initial height, a rocket is fired upward from ground level with an initial velocity of 1600 feet/sec. When does the

Question 103806This question is from textbook Precalculus A GRAPHING APPROACH
: My question is given the equation s=-16t^2+initial velocity x t+initial height, a rocket is fired upward from ground level with an initial velocity of 1600 feet/sec. When does the rocket reach its maximum height and how high is it at that time? This question is from textbook Precalculus A GRAPHING APPROACH

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
given the equation s=-16t^2+initial velocity x t+initial height, a rocket is fired upward from ground level with an initial velocity of 1600 feet/sec. When does the rocket reach its maximum height and how high is it at that time?
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EQUATION:
s(t) = -16t^2 + 1600x
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You have a quadratic with a = -16 and b = 1600
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Maximum height occurs when t = -b/2a = -1600/(-32) = 50 seconds
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Height at that time is s(50):
s(50) = -16(50^2) + 1600(50) = 40,000 ft.
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Cheers,
Stan H.
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