SOLUTION: Airplane A travels 2400 km at a certain speed. Plane B travels 1800 km at a speed 50 km/h faster than Plane A in 2 hours less time. Find the speed of each plane. Thank you

Question 1037668: Airplane A travels 2400 km at a certain speed. Plane B travels 1800 km at a speed 50 km/h faster than Plane A in 2 hours less time. Find the speed of each plane.
Thank you
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!

RATE TIME DISTANCE A r t 2400 B r+50 t-2 1800

That must make sense to you first.

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Continue when that information does make sense.

Travel Rates Rule is RT=D to relate rate, time, distance.
Form this system of equations:

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Many algebraic steps needed in solving the system for r and t.
You would make a couple of different substitutions through the process.

Starting with the "1800" equation,

Use the first equation of the system to make substituion:

Now you will make another substitution using the "2400" equation either solved for r or solved for t...
Answer by MathTherapy(10552) (Show Source): You can put this solution on YOUR website!

Airplane A travels 2400 km at a certain speed. Plane B travels 1800 km at a speed 50 km/h faster than Plane A in 2 hours less time. Find the speed of each plane.
Thank you

Let plane A�s speed be S
Then lane B�s speed is: S + 50
Time plane A takes: , while plane B takes:
We then get the following TIME equation:
2,400(S + 50) = 1,800S + 2S(S + 50) ------- Multiplying by LCD, S(S + 50)

(S - 400)(S + 150) = 0
S � 400 = 0 OR S + 150 = 0 (ignore)
S, or speed of plane A =
Speed of plane B: 400 + 50, or
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