SOLUTION: Find three consecutive odd integers such that the square of the third integer plus the product of the other two integers is 268. Thank you

Question 1037647: Find three consecutive odd integers such that the square of the third integer plus the product of the other two integers is 268.
Thank you
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Find three consecutive odd integers such that the square of the third integer plus the product of the other two integers is 268.
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Use n-2, n & n+2
(n+2)^2 + n(n-2) = 268
n^2+4n+4 + n^2-2n = 268
2n^2 + 2n + 4 = 268
n^2 + n - 132 = 0
n = -12, n = 11

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