SOLUTION: I am checking my work to the problem below:
find all real solutions to the quadratic equation; 6p+2=p^2+3p^3
6p+2=p^2+3p^3
6p+2=3p^3+p^2
6p+2−(3p^3+p^2)=3p^3+p^2ͨ
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Question 1037502: I am checking my work to the problem below:
find all real solutions to the quadratic equation; 6p+2=p^2+3p^3
6p+2=p^2+3p^3
6p+2=3p^3+p^2
6p+2−(3p^3+p^2)=3p^3+p^2−(3p^3+p^2)
−3p^3−p^2+6p+2=0
(−3p−1)(p^2−2)=0
−3p−1=0 or p^2−2=0
p= -1/3
Found 2 solutions by Alan3354, josgarithmetic:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
find all real solutions to the quadratic equation; 6p+2=p^2+3p^3
6p + 2 = p^2 + 3p^3
6p+2 = 3p^3 + p^2
************
3p^3 + p^2 - 6p - 2 = 0
p^2*(3p + 1) - 2*(3p + 1) = 0
(p^2 - 2)*(3p + 1) = 0
p = -1/3
=============
p^2 - 2 = 0
p = sqrt(2)
p = -sqrt(2)
*************************
6p+2 - (3p^3+p^2) = 3p^3 + p^2 - (3p^3+p^2)
-3p^3−p^2+6p+2=0
(−3p−1)(p^2−2)=0
−3p−1=0 or p^2−2=0
p= -1/3
Answer by josgarithmetic(39616) (Show Source): You can put this solution on YOUR website!
Rearrangement should be as . Some other arrangement might allow easier factoring.
ZERO PRODUCT RULE
if , then .
-
If , then , or .
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