SOLUTION: My problem is if the vertex of f(x)=x^2+bx+c is at (2,4), find b and c.

Question 103749This question is from textbook Precalculus A GRAPHING APPROACH
: My problem is if the vertex of f(x)=x^2+bx+c is at (2,4), find b and c. This question is from textbook Precalculus A GRAPHING APPROACH

Found 2 solutions by scott8148, edjones:
Answer by scott8148(6628) (Show Source): You can put this solution on YOUR website!
for a parabola with the vertex at (h,k) ... y=a(x-h)^2+k ... f(x)=x^2-4x+4+4 ... f(x)=x^2-4x+8

b=-4 and c=8

the coefficient of the x^2 term in the original equation is 1 so a=1
Answer by edjones(8007) (Show Source): You can put this solution on YOUR website!
Standard form of the quadratic equation
The vertex point is (h,k).
h=2 k=4
f[x]=a(x-2)^2+4
=x^2-4x+4+4 (let a=1)
=x^2-4x+8
So, b=-4 and c=8
Ed

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