SOLUTION: Please help me with this problem :Elaine shoots an arrow upward at a speed of 32 feet per second from a bridge that is 28 feet high. The height of the arrow is given by the functio

Question 1034543: Please help me with this problem :Elaine shoots an arrow upward at a speed of 32 feet per second from a bridge that is 28 feet high. The height of the arrow is given by the function h(t) = -16t2+32t + 28, where t is the time in seconds.
a. What is the maximum height that the arrow reaches?
b. How long does it take the arrow to reach its maximum height?
c. How long would it take before the arrow reached the ground? Round your answer to the hundredths place.
Found 2 solutions by fractalier, ikleyn:
Answer by fractalier(6550) (Show Source): You can put this solution on YOUR website!
a) It reaches a maximum height when the velocity is zero.
v(t) = 0 = h'(t) = -32t + 32 ==> t=1 second
b) At that time, h(1) = -16 + 32 + 28 = 44 feet
c) To find this, we let h(t) = 0 and solve for t...thus
-16t^2 + 32t + 28 = 0
-4t^2 + 8t + 7 = 0
4t^2 - 8t - 7 = 0
and
t = 2.66 seconds
Answer by ikleyn(52780) (Show Source): You can put this solution on YOUR website!
.
Was solved in https://www.algebra.com/algebra/homework/quadratic/Quadratic_Equations.faq.question.1034230.html

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