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I am working on solving quadratic equations with substitutions.
(y-10/y)^2-6(y'10/y)-27=0
I have done the substitution step, letting (y-10/y)=W. I solved for W. W=9 or -3 from what I got.
Now I am having difficulty inputting those answers back into the equation to solve for y. y-10/y=9 or y-10/y=-3.
Any help is greatly appreciated. Thank you
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= 9 ---> multiply both sides by y --->
y - 10 = 9y,
-10 = 9y - y,
-10 = 8y,
y = .
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= -3 ---> multiply both sides by y --->
y - 10 = -3y,
-10 = -3y - y,
-10 = -4y,
y = .