SOLUTION: Can anyone tell me if I did this correctly? 3/x + 2 + x/x^2-4 This is what I did. I took the x^2 - 4 and changed it to (x+2)(x-2) and then crossed out both (x + 2) which

Question 10335: Can anyone tell me if I did this correctly?

3/x + 2 + x/x^2-4

This is what I did. I took the x^2 - 4 and changed it to (x+2)(x-2) and then crossed out both (x + 2) which left me with this answer:

3x/x-2

Is this correct? Thanks for your help. I appreciate it.
Answer by rapaljer(4671) (Show Source): You can put this solution on YOUR website!
If your question is this, as I suspect it is:

then you missed it. If it's NOT what I am suggesting, then you still missed it!! Sorry about that!

You are correct to factor the second denominator.

Next, since this is an addition problem, you must find a common denominator, which is (x-2)(x+2). The second fraction already has the common denominator, so it is good to go!! However, the first fraction is missing something. It's missing a factor of (x-2). So you have to multiply numerator and denominator of the first fraction by (x+2). It looks like this:

Now, put down the common denominator for the denominator of your answer, and for the numerator of your answer, you have to add the numerators of the two fractions:

Combine like terms in the numerator:

You might try to factor the numerator, but it doesn't reduce, so either the previous answer or the factored form is acceptable:

R^2 at SCC

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