SOLUTION: the evidence of an illegal gun operation consisted of two different types of guns. the pistols are worth $565 a piece and the rifles are worth $795 a piece. If there are two times

Algebra.Com
Question 1033266: the evidence of an illegal gun operation consisted of two different types of guns. the pistols are worth $565 a piece and the rifles are worth $795 a piece. If there are two times as many rifles as there are pistols, and all the guns combined are worth $75,425, how many rifles and pistols are being held in evidence?
Answer by addingup(3677)   (Show Source): You can put this solution on YOUR website!
R=2P
565P+795(2P)=75425
565P+1590P=75425
2155P=75425
P=75425/2155 35 and R=2(35)=70
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
John

RELATED QUESTIONS

A special-interest group has conducted a survey concerning a ban on hand guns. Note: A... (answered by ewatrrr)
A toymaker makes soldiers and guns from wood and plastic. The store has 60 units of wood... (answered by greenestamps)
A construction crew foreman is buying k two-by-four boards for farming a house. She is... (answered by Theo)
The equation y= -1777x + 27,153 can be used to predict the number of y gun deaths in the... (answered by tutorcecilia)
what are the different types of... (answered by jim_thompson5910)
a pizza shop has 10 different toppings, three types of crust, and two types of sauce. how (answered by macston)
The passengers on an excursion bus consisted of 14 married couples , 8 of whom brought... (answered by ikleyn)
An artillery observer in an airplane agrees that when he gets above a target which is... (answered by Alan3354)
The probability that an American household has a gun is 0.34 . Five American households... (answered by ewatrrr)