SOLUTION: The perimeter of a square and a rectangle are equal. One side of the rectangle is 11 cm and the area of the square is 4 cm^2 more than the area of the rectangle. Find the side of

Question 1032429: The perimeter of a square and a rectangle are equal. One side of the rectangle is 11 cm and the area of the square is 4 cm^2 more than the area of the rectangle. Find the side of square
Answer by jorel555(1290) (Show Source): You can put this solution on YOUR website!
Let x=one side of the square; y=one side of the rectangle:
The perimeters are equal, so 4x=2y+22, or y=2x-11. The areas are given by x^2, and 11(2x-11). Since the square is 4 cm^2 larger than the rectangle, we get:
x^2-4=11(2x-11)
x^2-4=22x-121
x^2-22x+117=0
(x-13)(x-9)=0
x=13, or 9
Plugging 13 into our original equation, we get a square 13X13 or 169cm^2, and a rectangle (26-11)X 11, or 165cm^2, which satisfies our requirements!!!!!!!

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