SOLUTION: Two numbers differ by 3 . The sum of their reciprocal is 7/10 find the numbers

Question 1032428: Two numbers differ by 3 . The sum of their reciprocal is 7/10 find the numbers
Found 2 solutions by stanbon, josmiceli:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Two numbers differ by 3 . The sum of their reciprocal is 7/10 find the numbers
-----------
x - y = 3
(1/x) + (1/y) = 7/10
---------------------------
x - y = 3
10y + 10x = 7
---------------------
x - y = 3
x + y = 0.7
-----
2x = 3.7
x = 1.85
-----
y = 0.7-1.85 = -1.15
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Cheers,
Stan H.
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
Let the numbers be and
(1)
(2)
---------------------
(1)
and
Multiply both sides of (2) by
(2)
(2)
(2)
Substitute (1) into (2)
(2)
(2)
(2)
Use quadratic formula

So,
and
(1)
(1)
(1)
The numbers are 2 and 5
check:
(2)
(2)
(2)
(2)
OK
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