SOLUTION: Find a quadratic model for the set of values: (-2, -20), (0, -4), (4, -20)
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Question 1032297: Find a quadratic model for the set of values: (-2, -20), (0, -4), (4, -20)
Found 2 solutions by josgarithmetic, solver91311:
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
You should be able to take advantage of the given root and the easily found symmetry axis with the use of the standard form equation.
Two x values give the same y value of . This tells you where the symmetry axis is.
----a starter equation
Point (-2,-20) gives
and
point (4,-20) gives
and the system easily solvable.
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
A quadratic function has the form:
\ =\ ax^2\ +\ bx\ +\ c)
If \right)\ =\ (-2,-20))
then
^2 +\ b(-2)\ +\ c\ =\ -20)
Likewise, for \right)\ =\ (0,-4))
and \right)\ =\ (4,-20))
^2 +\ b(0)\ +\ c\ =\ -4)
and
^2 +\ b(4)\ +\ c\ =\ -20)
Which yields the 3X3 system:
Which can be simplified to the 2X2 system:
Solve the 2X2 system for 
and 
. You already know that 
John
My calculator said it, I believe it, that settles it
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