SOLUTION: Write a quadratic equation in standard form with the given solutions.
The hypotenuse of a right triangle measures 8 in. More than one leg and 3 in. More than the other leg. Find
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Question 1029997: Write a quadratic equation in standard form with the given solutions.
The hypotenuse of a right triangle measures 8 in. More than one leg and 3 in. More than the other leg. Find the lengths of the sides of the triangle ( to the nearest tenth of an inch).
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
Hypotenuse = x
leg 1 = x-8
leg 2 = x-3
Find the roots of the equation by quadratic formula
a= 1 b= -22 c= 73
b^2-4ac= 484 - 292
b^2-4ac= 192 = 13.86
x1=( 22 + 13.86 )/ 2
x1= 17.93
x2=( 22 -13.86 ) / 2
x2= 4.07
Since one leg is 8 cm less than the hypotenuse
x= 17.93
leg 1 = 17.93-8 = 9.93
leg 2 = 17.93 -3= 14.93
Check
9.93^2+14.93^2=321.5098
17.93^2= 321.4849
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