SOLUTION: Solve by complementing the square 1/2x^2 + 3x =17

Question 1028884: Solve by complementing the square
1/2x^2 + 3x =17
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
=

(1/2)x^2 + 3x =1
multiply by 2
x^2+6x =2
Third term can be found out by the formula
(1/2* coefficient of middle term )^2
((1/2)*6)^2
=9

x^2 + 6x+9 =2+9
(x+3)^2 = 11
x+3= +/-sqrt(11)
x= -3 +/- sqrt(11)

RELATED QUESTIONS
{{{2x^2-3x+1=0}}}Solve by completing the... (answered by Earlsdon)

2x^2-3x+1=0 Solve by completing the square. (answered by nerdybill,Edwin McCravy)

Solve by completing the square : 7 = 3x - 2x^2 (answered by funmath)

Solve by completing the square. 2x^2 - 3x + 5 =... (answered by faceoff57)

Solve by completing the square: 3x^2 - 10=... (answered by josmiceli)

Solve by completing the square:... (answered by josgarithmetic)

can you please help me solve by completing the square of:... (answered by Mathtut)

can you please help me solve by completing the square of ((( 2x^2-3x+1=0... (answered by solver91311)

Solve the system by substitution. Show all work! 2x � 2y = 2 y = 3x � 17 (answered by SHUgrad05)