SOLUTION: Please help me! Thanks (: Approximate the zeros of the function. Round to the nearest tenth. 1.) y=x^2-7x+7 2.) y=-2x^2-9x+10

Question 1028737: Please help me! Thanks (:

Approximate the zeros of the function. Round to the nearest tenth.

1.) y=x^2-7x+7

2.) y=-2x^2-9x+10

Answer by rothauserc(4718) (Show Source): You can put this solution on YOUR website!
We use Newton's method to approximate zeros
:
x(n+1) = x(n) - (f(x(n)) / f'(x(n)))
:
1) y = x^2-7x+7
Consider the graph of this equation

:
The zeros are close to 1 and 6, I will show you how to find the zero close to 1. All others follow the same procedure.
:
Calculate f'
:
f' = 2x-7
:
Let x(0) = 1, then
:
x(1) = x(0) - (f(x(0)) / f'(x(0))
:
x(1) = 1 - (1 / -5) = 1.2
:
x(2) = 1.2 - (0.04 / -4.6) approx 1.2
:
Since x(2) = x(1), there is no point in continuing
:
f(1.2) = 0.04 approximately 0.0, therefore
:
x = 1.2 is a good approximation for a zero
:

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