SOLUTION: When a ball is served, consider the trajectory of ball modelled by equation y=-x^2/8 + 9x/8 +5/4. Find the height of the ball when it is 3m horizontally from where served. (Y repr

Question 1028260: When a ball is served, consider the trajectory of ball modelled by equation y=-x^2/8 + 9x/8 +5/4. Find the height of the ball when it is 3m horizontally from where served. (Y represents height of ball in metres above ground and x represents horizontal distance from when ball was struck).
I believe 5/4 (y intercept)represents the initial height and that the ball travels 10m (x intercept) but I'm stuck with how to calculate the height after 3 metres.
any help/advice would be great
Thanks
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
When a ball is served, consider the trajectory of ball modelled by equation y=-x^2/8 + 9x/8 +5/4.
Find the height of the ball when it is 3m horizontally from where served.
(Y represents height of ball in metres above ground and x represents horizontal distance from when ball was struck).

find y when x=3

y = 3.5 meters is the height
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