Question 1027817: Solving using the quadratic formula.
7x(x+2)+5=3x(x+1)
Do you first subtract the 3x^2 from 7x^2? I'm not 100% on how to work this through. Found 3 solutions by Cromlix, Theo, MathTherapy:Answer by Cromlix(4381) (Show Source): You can put this solution on YOUR website! Hi there,
7x(x+2)+5=3x(x+1)
7x^2 + 14x + 5 = 3x^2 + 3x
7x^2 - 3x^2 + 14x - 3x + 5 + 0
4x^2 + 11x + 5 = 0
Solve using:-
a = 4, b = 11 and c = 5 :
x = -0.575 x = -2.175 (2 decimal places)
Hope this helps :-) Answer by Theo(13342) (Show Source): You can put this solution on YOUR website! you want to get the quadratic equation into standard form first.
that form is ax^2 + bx + c = 0
a is the coefficient of the x^2 term.
b is the coefficient of the x term.
c is the constant term.
your equation is:
7x(x+2)+5=3x(x+1)
simplify by performing the operations indicated to get:
7x^2 + 14x = 3x^2 + 3x
not subtract all the terms on the right hand side from both sides of the equation to get:
7x^2 + 14x - 3x^2 - 3x = 0
now combine like terms to get:
4x^2 + 11x = 0
it is now in standard form of ax^2 + bx + c = 0
a = 4
b = 11
c = 0
now you can use the quadratic formula of x = (-b plus or minus sqrt(b^2-4ac)/(2a).
that will get you x = 0 or x = -22/8 which can be simplified to x = -11/4.
the graph of the resulting equation confirms that, as shown below:
the decimal equivalent of -11/4 is -2.75, as shown on the graph.
7x(x + 2) + 5 = 3x(x + 1) -------- Distributing ----- Subtracting from each side, as you surmised
Solve using the quadratic equation formula, as instructed.
a = 4
b = 11
c = 5