SOLUTION: Put the function y=10x(x+6) in factored form f(x)=a(x-r)(x-s) and state the values of a, r, and s.
a=
r=
s=
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Question 1027809: Put the function y=10x(x+6) in factored form f(x)=a(x-r)(x-s) and state the values of a, r, and s.
a=
r=
s=
Answer by Theo(13342) (Show Source): You can put this solution on YOUR website!
i'm not exactly sure what they are looking for.
the equation looks like it is already in factored form.
it appears to be 10 * (x+6) * (x + 0).
the form they are looking for is a * (x-r) * (x-s)
if i'm guessing correctly, then you would get:
a = 10
r = -6
s = 0
the unfactored equation would be 10x^2 + 60x = 0
you would factor out the gcf to get 10 * (x^2 + 6x)
if you tried to factor the quadrtic of x^2 + 6x using the quadratic formula, you would get:
a = 1
b = 6
c = 0
sqrt(b^2 - 4ac) = sqrt(36-4*1*0) = sqrt(36) = 6
quadratic formula of x = (-b +/- sqrt(b^2-4ac))/(2a) would become:
x = (-6 + 6) / 2 or x = (-6 -6) / 2
this would result in x = 0 or x = -6
one of the factors would be x.
the other factor would be x + 6
that agrees with what is shown.
i can't think of any other way to force the result to be in the form indicated.
i'll stick with my guess.
a = 10
r = -6
s = 0
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