SOLUTION: The height of a rock above the ground is given by the equation h=-16t^2+24t+16. T is the time in seconds after the rock is thrown. It is thrown upward from a platform 16 feet above
Algebra.Com
Question 1027481: The height of a rock above the ground is given by the equation h=-16t^2+24t+16. T is the time in seconds after the rock is thrown. It is thrown upward from a platform 16 feet above the ground. After how many seconds is the rock back to a height of 16 feet?
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
I want 2 solutions for
One of the solutions is when
---------------
Set again
Subtract from both sides
In 1.5 sec, the rock is on it's way down
and is at a height of 16 ft
------------------------
Here's the plot:
RELATED QUESTIONS
A rock is tossed straight up with initial velocity of 10 feet per second from atop a... (answered by josmiceli)
The height h of a rock t seconds after it is dropped off a cliff is given by the equation (answered by Boreal)
the height "h" of a rock, "t" seconds after it is dropped off a cliff is given by the... (answered by josmiceli)
A rock is thrown upward from the ground with an initial velocity of 96 feet per second.... (answered by midwood_trail)
A rock is thrown straight up into the air from a height of 4 feet, the height of the rock (answered by nerdybill)
A man is standing over a beach and throws a rock up in the air from a height of 192ft.... (answered by ankor@dixie-net.com)
The height h of an object t seconds after it is dropped off a building is given by the... (answered by stanbon)
Benjamin threw a rock straight up from a cliff that was 48 ft above the water. If the... (answered by josmiceli,ikleyn)
If a rock is thrown upwards with an initial velocity of 25 m/s from a cliff
that is 5... (answered by jorel1380,ikleyn)