Sorry but x² - 8x - 3 does not factor. Did you copy it wrong? However x² - 8x + 15 does factor. We assume it factors as (x-a)(x-b), so then: x² - 8x + 15 = (x-a)(x-b), Substitute x=10 10² - 8∙10 + 15 = (10-a)(10-b) 100-80+15 = (10-a)(10-b) 35 = (10-a)(10-b) 35 factors as 7∙3 so So we set 10-a = 7 and 10-b = 5 That gives: a = 3 and b = 5 So (x-a)(x-b) becomes (x-3)(x-5) Edwin