SOLUTION: Solve. 5(x-2)^2=3 a. 1/5 19/5 b. 10+-square root15over 5 c. 10+-square root3 over 5 d. +- 59 over 25

Question 102584: Solve. 5(x-2)^2=3
a. 1/5 19/5
b. 10+-square root15over 5
c. 10+-square root3 over 5
d. +- 59 over 25
Found 2 solutions by jim_thompson5910, edjones:
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Start with the given equation

Divide both sides by 5

Take the square root of both sides

Break up the root

Multiply the right side by

Combine the roots and multiply

Add 2 to both sides

Combine the two fractions

So our answer is which means our answer is B
Answer by edjones(8007) (Show Source): You can put this solution on YOUR website!
5(x-2)^2=3
5(x^2-4x+4)=3
5x^2-20x+20=3
5x^2-20x+17=0
The answer is b 10+-square root15over 5
Ed

Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=60 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: 2.77459666924148, 1.22540333075852. Here's your graph:

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