SOLUTION: the length of a rectangle is represented by x+7 and the width is represented by x+1. If the area of the rectangle is 65 square feet, find the perimeter of this rectangle.

Question 1025580: the length of a rectangle is represented by x+7 and the width is represented by x+1. If the area of the rectangle is 65 square feet, find the perimeter of this rectangle.
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
Length = (x+7)
width = (x+1)
Area = L * W
(x+7)(x+1) =65

y=1x2+8x−58 discriminant=b2−4(a)(c)=82−4(1)(−58)=296 ( 2 real solutions )

−b� sqrt(b2−4(a)(c))/√2(a)

−8�82−4(1)(−58)/2(1)
−8�296/2
=−8�4�74 /2
=−8�274 /2
=−4�174
=−4�174

x=4.602325267042627 x=−12.602325267042626
ignore negative
x=4.6
length = 11.6 & width = 5.6
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