SOLUTION: Find the area of the region enclosed by the graph of the equation x^2 + y^2 = 4x + 6y+13.

Question 1025025: Find the area of the region enclosed by the graph of the equation x^2 + y^2 = 4x + 6y+13.

Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Find the area of the region enclosed by the graph of the equation x^2 + y^2 = 4x + 6y+13.
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x^2 + y^2 = 4x + 6y+13.
x^2-4x + y^2-6y = 13.
Complete the square for x & y.
x^2-4x+4 + y^2-6y+9 = 13+4+9 = 26
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r^2 = 26

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