SOLUTION: Determine the equation of the parabola with vertex (-2,5) and that passes through (4,-8)

Question 102482: Determine the equation of the parabola with vertex (-2,5) and that passes through (4,-8)
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Determine the equation of the parabola with vertex (-2,5) and that passes through (4,-8)
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Vertex form of a parabola:
(4p)(y-k) = (x-h)^2
Substitute to find "4p"
4p(-8-5) = (4+2)^2
4p(-13) = 36
4p = -36/13
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EQUATION:
(-36/13)(y-5)=(x+2)^2
Multiply both sides by 13 to get:
-36(y-5) = 13[x^2+4x+4]
-36y + 180 = 13x^2+52x+52
-36y = 13x^2+52x-128
y = -13/36)x^2-(13/9)x+(13/9)
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Cheers,
Stan H.

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