SOLUTION: The graph of the equation y =ax^2 + bx + c, where a, b, and c are constants, is a parabola with axis of symmetry x = -3. Find b/a

SOLUTION: The graph of the equation y =ax^2 + bx + c, where a, b, and c are constants, is a parabola with axis of symmetry x = -3. Find b/a

Algebra.Com

Question 1024598: The graph of the equation y =ax^2 + bx + c, where a, b, and c are constants, is a parabola with axis of symmetry x = -3. Find b/a
Answer by richard1234(7193) (Show Source): You can put this solution on YOUR website!
The x-coordinate of the vertex is at x = -b/2a, so -3 = -b/2a <==> b/a = 6.
RELATED QUESTIONS
The graph of the equation $y =ax^2 + bx + c$, where $a$, $b$, and $c$ are constants, is (answered by jim_thompson5910)

Find a+b+c if the graph of the equation y=ax^2+bx+c is a parabola with vertex (5,3), a... (answered by josgarithmetic)

The graph of y=ax^2 + bx + c is a parabola with vertical axis of symmetry. The vertex of... (answered by solver91311)

In the xy-plane, if the parabola with equation y = ax^2 + bx + c, where a,b,and c are... (answered by ikleyn)

Find an equation of the circle with center at (-3,-3)that is the tangent to the y-axis in (answered by josgarithmetic)

what is the sum of the roots of the quadratic equation: ax^2 + bx + c = 0, where a, b,... (answered by Fombitz)

find the equation of the axis of symmetry and the coordinates of the vertex of the graph... (answered by mathsteacher)

A parabola has intercepts of x = -2, x = 3, and y = -4. a. Write the intercept form of (answered by josgarithmetic,Edwin McCravy)

The graph of y = ax^2 + bx + c has an axis of symmetry of x = -3. If y = a(x - h)^2 + k, (answered by ikleyn)