SOLUTION: A ball is thrown into the air with an initial upward velocity of 45 ft/s. Its height (h) in feet after t seconds is given by the function h=-16t^2 + 45t + 6. After about how many s
Algebra.Com
Question 1023904: A ball is thrown into the air with an initial upward velocity of 45 ft/s. Its height (h) in feet after t seconds is given by the function h=-16t^2 + 45t + 6. After about how many seconds will the ball hit the ground?
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
h=-16t^2 + 45t + 6. After about how many seconds will the ball hit the ground?
--------------
When -16t^2 + 45t + 6 = 0
Solve for t, ignore the negative solution.
RELATED QUESTIONS
A ball is thrown into the air with an upward velocity of 36 ft/s. Its height h in... (answered by solver91311)
A ball is thrown into the air with an upward velocity of 36 ft/s. Its height h in feet... (answered by Alan3354)
A ball is thrown into the air with the in initial upward velocity of 45 ft/s. It's height (answered by Alan3354)
A ball is thrown from an initial height of
4
feet with an initial upward velocity of (answered by Boreal)
A ball is thrown from an initial height of 4 feet with an initial upward velocity of 32... (answered by Alan3354)
A ball is thrown into the air with the in initial upward velocity of 60 ft/s. It's height (answered by Alan3354)
please help
A ball is thrown from an initial height of 5 feet with an initial upward... (answered by ikleyn)
Word Problem Help
A ball is thrown from an initial height of 4 feet with an initial... (answered by MathLover1)
a ball is thrown vertically upward with an initial speed of 48 ft/s. its height, in feet, (answered by richwmiller)