SOLUTION: The two positive integer solutions of the equation x^2 - mx + n = 0 are k and t, where m and n are both prime numbers and k > t. What is the value of m^n + n^m + k^t + t^k?
Algebra.Com
Question 1022588: The two positive integer solutions of the equation x^2 - mx + n = 0 are k and t, where m and n are both prime numbers and k > t. What is the value of m^n + n^m + k^t + t^k?
Answer by robertb(5830) (Show Source): You can put this solution on YOUR website!
RELATED QUESTIONS
Let n be a positive integer, k the number of prime numbers less than or equal to n, and... (answered by richard1234)
let k be an integer and p is a prime such that the quadratic equation x^2+kx+p=0 has two... (answered by ankor@dixie-net.com)
If 3+2i is a solution for x^2+mx+n=0, where m and n are real numbers, what is the value... (answered by jim_thompson5910)
If {{{ 3 + 2i }}} is a solution for {{{ x^2+mx+n=0 }}}, where m and n are real numbers,... (answered by stanbon)
If 2 + 2i is a solution for x2 + mx + n = 0, where m and n are real numbers, what is the... (answered by lynnlo)
If two prime numbers are roots of the equation x^2-12x+k=0, what is the value of... (answered by Boreal,ikleyn)
Prove that, log(n) >= k.log(2) (Where n >= 2 and "k" denote the number of distinct prime... (answered by richard1234)
1. Write an equation in the form y=ax^2+bx+c for the quadratic function whose graph... (answered by khwang)
If P(n,k)=120. Find the possible values of n and k. How many solutions are... (answered by Edwin McCravy,greenestamps)