SOLUTION: How can i solve for x using quadratic equation?? 2(1-k)x^2-4kx+k=0 im having trouble simplifying in the middle of using the formula. I know that a=(2-2k), b=-4, c=k

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Question 1019657: How can i solve for x using quadratic equation??
2(1-k)x^2-4kx+k=0
im having trouble simplifying in the middle of using the formula.
I know that a=(2-2k), b=-4, c=k
Found 2 solutions by stanbon, MathTherapy:
Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
2(1-k)x^2-4kx+k = 0
----------------
x = [4k +- sqrt[(-4k)^2-4*2(1-k)(-4k))]/(2(2(1-k))
============
Cheers,
Stan H.
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Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!

How can i solve for x using quadratic equation??
2(1-k)x^2-4kx+k=0
im having trouble simplifying in the middle of using the formula.
I know that a=(2-2k), b=-4, c=k
, but - 4k, instead. Maybe that's why you're having trouble. 

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