SOLUTION: Find k if the roots of the equation (k+3)x^2 - 2(k+1)x - (k+1) = 0 are equal. If k is not equal to -3.

Question 1015514: Find k if the roots of the equation (k+3)x^2 - 2(k+1)x - (k+1) = 0 are equal. If k is not equal to -3.
Found 2 solutions by Boreal, MathTherapy:
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
(k+3)x^2 - 2(k+1)x - (k+1) = 0
if the roots are zero, b^2-4ac=0
b^2=4ac
b^2=(-2(k+1))^2=4k^2+8k+4
4ac=4k^2+16k+12
set them equal
4k^2+8k+4=4k^2+16k+12
8k+4=16k+12
8k=-8
k=-1
2x^2=0
x=0,0
Answer by MathTherapy(10552) (Show Source): You can put this solution on YOUR website!

Find k if the roots of the equation (k+3)x^2 - 2(k+1)x - (k+1) = 0 are equal. If k is not equal to -3.

OR k = - 1 (ignore)
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