SOLUTION: 4x^2-3x-4=0

Question 1013684: 4x^2-3x-4=0
Answer by rothauserc(4718) (Show Source): You can put this solution on YOUR website!
4x^2 -3x -4 = 0
divide both sides of = by 4
x^2 -3x/4 -1 = 0
x^2 -3x/4 = 1
complete the square
x^2 -3x/4 +9/64 = 1 + 9/64
(x - 3/8)^2 = 64/64 + 9/64 = 73/64
x - 3/8 = (3/8) * sqrt(7)
x = (3/8) + ((3/8) * sqrt(7))
x = (3/8) * (1 + or - sqrt(7))
therefore
x = (3/8) * (1 + sqrt(7))
or
x = (3/8) * (1 - sqrt(7))

RELATED QUESTIONS
3x^2-4x-4=0 (answered by stanbon)

3x^2-4x=0 (answered by Theo)

3x^2-4x-4 (answered by jim_thompson5910)

4x-2=3x=4 (answered by rfer)

-4x+2=3x-4 (answered by jim_thompson5910)

3x^4(4x^2) (answered by ReadingBoosters)

4x + 2 < 3x -... (answered by ewatrrr)

4x^2 + 3x... (answered by xcentaur)

4x^2 + 3x -5... (answered by checkley71)