SOLUTION: 14y^2+1=6y^2+7y y=

Question 1012912: 14y^2+1=6y^2+7y
y=
Found 2 solutions by fractalier, Boreal:
Answer by fractalier(6550) (Show Source): You can put this solution on YOUR website!
Okay, from
14y^2 + 1 = 6y^2 + 7y
let's gather everything on the left, and get
8y^2 - 7y + 1 = 0
This does not factor over the rational numbers so we use the quadratic formula to get
y = (7 +/- sqrt(17)) / 16
but I suspect there is a mistake somewhere in the problem...
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
14y^2+1=6y^2+7y
8y^2-7y+1=0
y=(1/16)(7+/- (49-32)
y=(1/16)(7+/- sqrt (17)
====
numerically, this is about 0.69 and 0.18

RELATED QUESTIONS
solve my elimination: 3x-7y=1... (answered by Fombitz)
y^2+49+14y (answered by askmemath)
6y^3+25y^2+14y (answered by jim_thompson5910)
y^2-5y/y^2+7y+12 divided by... (answered by haileytucki)
Could someone please assist me by solving this logarithmic equation step-by-step for... (answered by scott8148,bimanewton)
linear algebra elimination method 13) 2/3x+2/5y=4/5 1/2x+2/3y=-1/2... (answered by Edwin McCravy)
add:... (answered by checkley71)
is this right 2x-Y=1 x=-3y+11 2(-3y+11)-y= 1 -6y+22-y=1 -7y+22=1 -7y=-21... (answered by mathrebel)
Find the LCM of 14y^2+42y and 7y^2+35y+42 The LCM is... (answered by KMST)