SOLUTION: How to find a turning point if you are given this expression : -2x^2+40x-600
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Question 1010872: How to find a turning point if you are given this expression : -2x^2+40x-600
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
How to find a turning point if you are given this expression : -2x^2+40x-600
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The "turning point" or vertex occurs when x = -b/(2a)
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Your Problem::
x = -b/(2a) = -40/(2*-2) = 10
Then y = f(10) = -2(10)^2 + 40(10) - 600 = -200+400-600 = -400
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Ans: Vertex is (10,-400)
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Cheers,
Stan H.
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