SOLUTION: Could someone please help me solve this equation?? Use the quadratic forumla.
{{{3x^2-2x+1=0}}}
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Question 100676: Could someone please help me solve this equation?? Use the quadratic forumla.
Found 2 solutions by checkley71, stanbon:
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
3X^2-2X+1=0
X=(2+-SQRT[-2^2-4*3*1]0/2*3
X=(2+-SQRT[4-12])/6
X=(2+-SQT-8)/6
X=2+-2.828i)/6
X=2/6+2.828i/6
X=1/3+.4714i ANSWER.
X=(2-2.828i)/6
X=2/6-2.828i/6
X=1/3-.4714i ANSWER.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
3x^2-2x+1=0
x = [2 +- sqrt(4-4*3*1)]/6
x = [2 +- isqrt(10)]/6
x = [2 + isqrt(10)}/6 or x = [2 - isqrt(10)]/6
=======================
Cheers,
Stan H.
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