SOLUTION: Could I get someone to show me how to solve this equation correctly? Use the quadratic formula to solve the following quadratic equation. {{{2x^2-5x=3}}}

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Question 100455: Could I get someone to show me how to solve this equation correctly?
Use the quadratic formula to solve the following quadratic equation.
Found 2 solutions by checkley71, edjones:
Answer by checkley71(8403)   (Show Source): You can put this solution on YOUR website!
2X^2-5X-3=0

X=(5+-SQRT[-5*2-4*2*-3])/2*2
Y=(5+-SQRT[25+24])/4
X=(5+-SQRT49)/4
X=(5+-7)/4
X=(5+7)/4
X=12/4
X=3 ANSWER.
X=(5-7)/4
X=-2/4
X=-1/2 ANSWER.
Answer by edjones(8007)   (Show Source): You can put this solution on YOUR website!

2x^2-5x-3=0 subtract 3 from each side
Ed
Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=49 is greater than zero. That means that there are two solutions: .




Quadratic expression can be factored:

Again, the answer is: 3, -0.5. Here's your graph:
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