SOLUTION: Use Descartes' Rule of Signs to state the number of possible positive and negative real zeros of the polynomial function. (Enter your answers as a comma-separated list.) P(x) = &#

Question 1003486: Use Descartes' Rule of Signs to state the number of possible positive and negative real zeros of the polynomial function. (Enter your answers as a comma-separated list.)
P(x) = −2x^3 + x^2 − 29x + 17

number of possible positive real zeros:
number of possible negative real zeros:
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
-2x^3 + x^2 - 29x + 17
positive there are 3 changes, so there can be 3 or 1 positive real roots.
negative
+2x^3+x^2+29x+17. There are 0 negative roots
That comes from -2(-x^3)+(-x)^2-29(-x)+17, which is 2x^3+ x^2+29x+17

There is one positive root of -0.584 and no negative roots
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