SOLUTION: A function of two variables is defined as f(x.y)=x^2+y^2+4x-6y+7. What is the minimum value of this function?
Algebra.Com
Question 1000563: A function of two variables is defined as f(x.y)=x^2+y^2+4x-6y+7. What is the minimum value of this function?
Answer by KMST(5328) (Show Source): You can put this solution on YOUR website!
Since for all values of and ,
for all values of and ,
so the minimum value is .
RELATED QUESTIONS
2) Solve for x.
5x^2=-19x-12... (answered by Alan3354,ewatrrr)
If a function f is defined by equation F(x,y)=(x^2.y^3),and F(a,b)=10 then what is the... (answered by Fombitz)
Let the function f be defined by
F(x)=x^2+28. If f(3y)=2f(y), what is the one possible... (answered by MathLover1)
The question is:
The quadratic function f is defined by f(x) = {{{4x^2 +5x +2}}}
a) (answered by Alan3354)
This is one question with different parts, please help. Thank you
Find the vertex, line... (answered by stanbon)
what is the minimum value of the function f(x)=... (answered by lwsshak3)
A fixed point of a function is defined as a value of x for which f(x)=x. Find the fixed... (answered by Fombitz)
A function is defined as f(x)= 2x+1.the value of X for which f(x), f(2x),f(4x) are in... (answered by amarjeeth123)
if the function f is defined for all numbers x by f (x)=2x-7 then what is the value of... (answered by ewatrrr)