# SOLUTION: a fraction is such that if the numerator is multiplied by three and the denominator reduced by three we get 18/11, but if the numerator is increased by eight and denominator is dou

Algebra ->  Algebra  -> Proportions  -> Lessons -> SOLUTION: a fraction is such that if the numerator is multiplied by three and the denominator reduced by three we get 18/11, but if the numerator is increased by eight and denominator is dou      Log On

 Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations! Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help!

 Algebra: Proportions Solvers Lessons Answers archive Quiz In Depth

 Click here to see ALL problems on Proportions Question 257462: a fraction is such that if the numerator is multiplied by three and the denominator reduced by three we get 18/11, but if the numerator is increased by eight and denominator is doubled we get 2/5. find the fraction.Found 2 solutions by richwmiller, drk:Answer by richwmiller(9135)   (Show Source): You can put this solution on YOUR website!let fraction =a/b 3a/(b-3)=18/11 (a+8)/2b=2/5 a=12 b=25 check 3*12/22=36/22=18/11 ok check 12+8/50=2/5 20/50=2/5 2/5=2/5 ok Answer by drk(1908)   (Show Source): You can put this solution on YOUR website!First let the fraction be a/b, where b not = 0. We start with the first bit of information: If the numerator is multiplied by three and the denominator reduced by three we get 18/11 translates to (i) if the numerator is increased by eight and denominator is doubled we get 2/5 translates to (ii) cross multiply in both (i) and (ii) to get (iii) (iv) pull the a and b parts to one side as (v) (vi) multiply (v) by 2 and (vi) by -9 to get (vii) (viii) add down to get (ix) So, a = 12 Sub this into (iv) we get (x) solving for b, we get b = 25. So our original fraction is