SOLUTION: Derivation of T ∝ √l Derivation of T = 2π√(l/g) T = Time Period of a pendulum l = length of the pendulum g = gravity

Question 999330: Derivation of T ∝ √l
Derivation of T = 2π√(l/g)
T = Time Period of a pendulum
l = length of the pendulum
g = gravity
Answer by fractalier(6550) (Show Source): You can put this solution on YOUR website!
The relationship between the pendulum's period T and the square root of the length of the string has a constant of proportionality equal to
2(pi)/sqrt(g)
The derivation of the overall formula is quite complicated...this formula is really an approximation that is only valid for small angles theta...
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SOLUTION: Derivation of T &#8733; &#8730;l Derivation of T = 2&#960;&#8730;(l/g) T = Time Period of a pendulum l = length of the pendulum g = gravity

SOLUTION: Derivation of T ∝ √l Derivation of T = 2π√(l/g) T = Time Period of a pendulum l = length of the pendulum g = gravity