SOLUTION: for a group of boxes all of the same girth (2x height + 2x width), the volume V varies directly as the length L.
If one of the boxes has a volume of 288 cu. in and length of 12 in
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-> SOLUTION: for a group of boxes all of the same girth (2x height + 2x width), the volume V varies directly as the length L.
If one of the boxes has a volume of 288 cu. in and length of 12 in
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Question 93281: for a group of boxes all of the same girth (2x height + 2x width), the volume V varies directly as the length L.
If one of the boxes has a volume of 288 cu. in and length of 12 in., what is the constant of proportionality for the group of boxes? Answer by Nate(3500) (Show Source):
You can put this solution on YOUR website! volume V varies directly as the length L
V / L
If one of the boxes has a volume of 288 cu. in and length of 12 in., what is the constant of proportionality for the group of boxes?
288 / 12 = 24
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