SOLUTION: The gravitational attraction between two bodies varies inversely as the square of the distance between them. If the force of attraction is 64 pounds when the distance between the b

Question 932103: The gravitational attraction between two bodies varies inversely as the square of the distance between them. If the force of attraction is 64 pounds when the distance between the bodies is 9 feet, what is the distance between them when the force is 36 pounds?
Found 2 solutions by ewatrrr, stanbon:
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
F = k/d^2
64 = k/81
k = 81(64) = 5184
.......
F = 5184/d^2
F = 36lb
d = √(5184/36) = 12' is the distance between them
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
The gravitational attraction between two bodies varies inversely as the square of the distance between them. If the force of attraction is 64 pounds when the distance between the bodies is 9 feet, what is the distance between them when the force is 36 pounds?
----
a = k/d^2
----
Solve for "k"::
64 = k/9^2
k = 9^2*64
----
Equation:
a = (9^2*64)/d^2
Your Problem::
36 = (9^2*64)/d^2
----
d^2 = (9^2*64)/(36)
d = (9*8)/6
distance = 12 ft
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Cheers,
Stan H
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