SOLUTION: one Halloween evening a wizard and a witch countes the number of m&m snacks they had eacch received as a result their trick or treating. The witch simply said that she had receiv

Question 784773: one Halloween evening a wizard and a witch countes the number of m&m snacks they had eacch received as a result their trick or treating. The witch simply said that she had received 7 of them. The wizard, being a math genius, noticed that if he divided 6times the number of m&m snacka that he received by five less than the number he received, he woukd have the square of the number of m&m snacks that he had received. Who had more m&ms, the witch or the wizard?
Answer by KMST(5328) (Show Source): You can put this solution on YOUR website!
= number of M&M snacks the wizard had received
= 6 times the number of M&M snacks the wizard had received
= five less than the number of M&M snacks the wizard received
= the square of the number of M&M snacks the wizard received

What the wizard says in words, translates as

To solve that equation, I would first multiply both sides of the equal sign times to eliminate the denominator, and get

Then, it can be transformed and factored:
-->-->-->-->
THe solutions to that equation are:
(which qould not make sense,
(maybe the wizard did not get any M&M), and
.
The wizard may have received 6 M&M's or none at all, but the witch, who got 7, had more M&M's.
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