SOLUTION: I have been asked to solve the proportion {{{(b-3)/5 = 2/b}}} So, b minus three, both over 5 equals 2 over b. I just cant remember the steps to solve. Thanks.

Algebra ->  Proportions -> SOLUTION: I have been asked to solve the proportion {{{(b-3)/5 = 2/b}}} So, b minus three, both over 5 equals 2 over b. I just cant remember the steps to solve. Thanks.      Log On


   

Question 757355: I have been asked to solve the proportion
%28b-3%29%2F5+=+2%2Fb
So, b minus three, both over 5 equals 2 over b.
I just cant remember the steps to solve. Thanks.
Answer by LearnWithMajor(33) About Me  (Show Source):
You can put this solution on YOUR website!
When solving proportions the first step is usually to cross multiply.
%28b-3%29%2F5+=+2%2Fb
b%28b-3%29+=+2%285%29
b%5E2-3b+=+10
b%5E2-3b-10=0 Now we have a quadratic equation which we can factor
%28b-5%29%28b%2B2%29=0
Setting both binomials equal to zero we get that b = 5 or -2.