SOLUTION: An army of 2400 men has a stock of food sufficient for 50 days. After 10 days 800 men joined the army. For how many days will the food be sufficient now? If the ratio of one was re

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Question 594368: An army of 2400 men has a stock of food sufficient for 50 days. After 10 days 800 men joined the army. For how many days will the food be sufficient now? If the ratio of one was reduced by 1/3 for how many days will the stock last?
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
An army of 2400 men has a stock of food sufficient for 50 days.
After 10 days 800 men joined the army.
For how many days will the food be sufficient now?
:
Find number of meal-days available: 2400*50 = 120,000 meal-days
:
Let d = no. of days after 800 men join the 2400 men after 10 days
2400(10) + d(2400+800) = 120000
24000 + 3200d = 120000
3200d = 120000 - 24000
3200d = 96000
d = 96000/3200
d = 30 more days
therefore
30+10 = 40 days of food
:
If the ration of one was reduced by 1/3 for how many days will the stock last?
I understand that to mean that 2/3 rather than 1 per days
40%2F%282%2F3%29 = 40 * 3/2 = 120/2 = 60 days instead of 40