# SOLUTION: perimiter of rectangle is 64cm the , the length is 4cm less than twice the width find the l&w I tried 4/64=32 2/32=16

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 Question 573941: perimiter of rectangle is 64cm the , the length is 4cm less than twice the width find the l&w I tried 4/64=32 2/32=16 Answer by solver91311(16897)   (Show Source): You can put this solution on YOUR website! I just did this one but here it is again: If a rectangle with perimeter has a length that is units longer (or shorter if ) than times the width, , Then knowing that the Perimeter is given by: , make the substitution: Then solve for For your problem: , , and . Do the arithmetic. John My calculator said it, I believe it, that settles it