SOLUTION: A car going 65 miles per hour traveled 15 miles farther tahn a car traveling 55 miles an hour in the same time. How far did each car travel during that time?

Algebra ->  Proportions -> SOLUTION: A car going 65 miles per hour traveled 15 miles farther tahn a car traveling 55 miles an hour in the same time. How far did each car travel during that time?      Log On


   



Question 521581: A car going 65 miles per hour traveled 15 miles farther tahn a car traveling 55 miles an hour in the same time. How far did each car travel during that time?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let t = time for both cars
Let d = distance traveled by slower car
For faster car:
(1) +d+%2B+15+=+65t+
For slower car:
(2) +d+=+55t+
Substitute (2) into (1)
(1) +55t+%2B+15+=+65t+
(1) +10t+=+15+
(1) +t+=+1.5+
and, since
(2) +d+=+55t+
(2) +d+=+55%2A1.5+
(2) +d+=+82.5+
+d+%2B+15+=+97.5+
The faster car traveled 97.5 mi
The slower car traveled 82.5 mi
check:
(1) +d+%2B+15+=+65t+
(1) +82.5+%2B+15+=+65%2A1.5+
(1) +97.5+=+97.5+
OK