SOLUTION: A 6-foot tall man is standing near a tree on level ground(the shadow of the tree is 18 feet long). If the man's shadow is 4 feet long, how many feet tall is the tree?

Algebra.Com
Question 51077: A 6-foot tall man is standing near a tree on level ground(the shadow of the tree is 18 feet long). If the man's shadow is 4 feet long, how many feet tall is the tree?
Answer by AnlytcPhil(1806)   (Show Source): You can put this solution on YOUR website!
A 6-foot tall man is standing near a tree on level ground(the shadow of the
tree is 18 feet long).  If the man's shadow is 4 feet long, how many feet tall
is the tree? 

---------------------------------------------

Man's height IS TO Man's shadow AS Tree's height IS TO Tree's shadow

Let the tree's height be x. Then we have

                   6 IS TO 4 AS x IS TO 18

Replace the "IS TO"'s by " / " and the "AS" by " = "

                     6/4 = x/18

Cross multiply:

                    4x = 6(18)
                    4x = 108
                     x = 27 feet

Edwin

RELATED QUESTIONS

a 6-foot tall man is standing near a tree on level ground, and the mans shadow is 4feet... (answered by vleith)
Can someone help me break this down? a 6-foot tall man is standing near a tree on... (answered by amoresroy)
A 6 FT. TALL MAN IS STANDING NEAR A TREE ON LEVEL GROUND. HIS SHADOW IS 4FT LONG. IF THE... (answered by stanbon)
A tree casts a shadow of 12 feet. At the same time a 6-foot man casts a 3-foot... (answered by checkley79)
When a tree casts a 20-foot shadow, a man 6 feet tall casts a 3-foot shadow. How tall is... (answered by josmiceli)
A 6-foot tall man casts a 10-foot shadow. At the same time and location, a tree casts a... (answered by nerdybill)
A 6 foot man casts a shadow that is 1 1/2 feet long. At the same time, a tree casts a... (answered by dragonwalker)
A tree 24 feet tall casts a shadow 16 feet long at the same time a man 6 feet tall casrs... (answered by stanbon)
With the sun, a six foot tall man casts a shadow that is 8 feet long. A nearby tree... (answered by KMST)