SOLUTION: Solve the proportion
(c+3)/(C-1) = (c+2)/(c-3)
Algebra.Com
Question 41361: Solve the proportion
(c+3)/(C-1) = (c+2)/(c-3)
Answer by tutorcecilia(2152) (Show Source): You can put this solution on YOUR website!
To begin, cross-multiply:
(c+3)(c-3) = (c-1)(c+2)
Multiply the factors using FOIL:
c^2 - 3c + 3c - 9 = c^2 + 2c - c - 2
Combine like terms:
c^2 - 9 = c^2 + - c - 2
Sovle for c:
c^2 - c^2 - 9 = c^2 -c^2 + - c - 2
- 9 = - c - 2
- 9 + 2 = - c - 2 + 2
-7 = c
Solve for c:
Checking the answer by plugging -7 back into the original equation:
(-7+3)/(-7-1) = (-7+2)/(-7-3)
-4/-8 = -5/-10
1/2 = 1/2 So, the answer checks out.
RELATED QUESTIONS
40. c+3/c-1 =... (answered by stanbon)
3(2-c)-c (answered by rfer)
(c)(c)(3)(c) (answered by drk)
c/3-2=1 (answered by stanbon)
C-5/c+3/c=2/3 (answered by checkley79)
(c+3)/(c-3)=(c+2)/(c-3) (answered by stanbon)
Solve the proof:
1. (AvB)->D
2. D-> (c->E)
3. A&C
:. E
(answered by jim_thompson5910)
-c^(2/3)(c^(1/3)+2c^(4/3)) (answered by Tatiana_Stebko)
Solve: 3 pt 1 c + 4 pt 1 c... (answered by Fombitz)