# SOLUTION: The volumes of 3 balloons are in the ratio 5:6:7. By what fractions of themselves must the first two be increased so that the ratio of the volumes may be changed to 7:6:5?

Algebra ->  Proportions -> SOLUTION: The volumes of 3 balloons are in the ratio 5:6:7. By what fractions of themselves must the first two be increased so that the ratio of the volumes may be changed to 7:6:5?      Log On

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 Question 402070: The volumes of 3 balloons are in the ratio 5:6:7. By what fractions of themselves must the first two be increased so that the ratio of the volumes may be changed to 7:6:5?Answer by edjones(7794)   (Show Source): You can put this solution on YOUR website!The volumes of 3 balloons are in the ratio 5:6:7. Let the vol. of the balloons be 5, 6 and 7L respectively The vol of the last balloon will be unchanged and will be 5/18 of the total volume after the first 2 are inflated more. 5x/18=7 for the 3rd balloon after the 1st 2 have their volumes increased x=25.2 . 6*25.2/18=8.4L new vol of the 2nd balloon. . 7*25.2/18=9.8L new vol of the 1st balloon. . Fraction of themselves the 1st two must be increased so that the ratio of the volumes may be changed to 7:6:5 8.4/6 = 7/5 9.8/5 = 49/25 . Ed